Theory of complexity   (translated from French)
... size of its authority. Classify NSPACE or NPSPACE : the problems décidables by an algorithm not ... inclusions: P ? NP and Co-Np ? PSPACE = NPSPACE. Np-Complete problem That is to say ... Conversely it is known that NPSPACENPSPACE
http://fr.wikipedia.org/wiki/Théorie_de_la_complexité - 20k - Cached (French) - Wikipedia (French) - Similar pages

Polynomial space
... verified in polynomial space is known as NPSPACE. Equivalently, NPSPACE is the class of decision problems that ... space on a non-deterministic Turing machine (NPSPACE stands for Nondeterministic Polynomial space). By Savitch's theorem, PSPACE = NPSPACE. See also PSPACE Computational complexity theory Complexity ...
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NSPACE   (translated from German)
... different complexity classes are defined. So can NPSPACE as follows from NSPACE to be deduced: $\backslash mbox\{$NPSPACE} = \bigcup_{k \in \mathbb{N}} \mbox{NSPACE ...
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List of complexity classes   (translated from German)
... problems in Polynomialzeit to reduce leave themselves. NPSPACE $\backslash bigcup\_\{c>0\}NSPACE(ñc)$NPSPACE corresponds) PSPACE completely The most difficult problems ...
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Classify complexity   (translated from French)
... size of its authority. Classify NSPACE or NPSPACE : the problems décidables by an algorithm not ... in NP and Co-Np in PSPACE = NPSPACE.
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User:Creidieki/NL rewrite
... of nondeterministic space , we have the class NPSPACE; allowing exponential amounts of nondeterministic space gives ... and EXPSPACE (see Proof that PSPACE equals NPSPACE ).
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Space hierarchy theorem
... to show that NL $\backslash subset$ NPSPACE, and using Savitch's theorem to show that PSPACE = NPSPACE. Corollary 4 PSPACE $\backslash subset$ EXPSPACE ...
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NSPACE
... deterministic counterpart of DSPACE. The complexity class NPSPACE can be defined in terms of NSPACE as follows: $\backslash mbox\{$NPSPACE} = \bigcup_{k\in\mathbb{N}} \mbox{NSPACE ...
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NSPACE   (translated from Spanish)
... not-determinist of DSPACE. The complexity class NPSPACE it is possible to be defined from NSPACE like: $\backslash mbox\{$NPSPACE} = \bigcup_{k\in\mathbb{N}} \mbox{NSPACE ...
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Sentence of Savitch   (translated from German)
... Savitch is the equality of PSPACE and NPSPACE. Formal definition Is $s:\; \backslash mathbb\{N\; ...$
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